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Python zur automatischen Auswahl serieller Ports (für Arduino)

Derzeit muss das Python-Programm wissen, an welchem ​​Port ein Gerät (Arduino) aktiv ist, bevor Python das Gerät kommunizieren kann.

Problem: Wenn das Gerät aus- und wieder eingesteckt wird, ändert sich der COM-Anschluss. Daher muss der richtige serielle Anschluss erneut an Python übergeben werden, damit das Gerät gefunden werden kann. 

Wie kann Python (mit pySerial) automatisch nach dem richtigen seriellen Port suchen, der verwendet werden soll? Kann Python das Gerät an einem seriellen Port als Arduino richtig identifizieren?

17
Nyxynyx

Verwenden Sie den folgenden Code, um alle verfügbaren seriellen Anschlüsse anzuzeigen:

import serial.tools.list_ports
ports = list(serial.tools.list_ports.comports())
for p in ports:
    print p

Das gibt mir folgendes:

('COM4', 'Arduino Due Programming Port (COM4)', 'USB VID:PID=2341:003D SNR=75330303035351300230')
('COM11', 'RS-232 Port (COM11)', 'FTDIBUS\\VID_0856+PID_AC27+BBOPYNPPA\\0000')

Um herauszufinden, ob es sich um ein Arduino handelt, können Sie Folgendes tun:

    if "Arduino" in p[1]:
        print "This is an Arduino!"
25
Matt Williams

Mit serial.tools.list_ports.comports können wir ein Arduino finden und verbinden mit:

import warnings
import serial
import serial.tools.list_ports

arduino_ports = [
    p.device
    for p in serial.tools.list_ports.comports()
    if 'Arduino' in p.description
]
if not arduino_ports:
    raise IOError("No Arduino found")
if len(arduino_ports) > 1:
    warnings.warn('Multiple Arduinos found - using the first')

ser = serial.Serial(arduino_ports[0])

Wenn Sie wissen, dass Sie jedes Mal genau das gleiche Arduino suchen, können Sie stattdessen nach p.serial_number filtern

import serial.tools.list_ports

def find_arduino(serial_number):
    for pinfo in serial.tools.list_ports.comports():
        if pinfo.serial_number == serial_number:
            return serial.Serial(pinfo.device)
    raise IOError("Could not find an arduino - is it plugged in?")

ser = find_arduino(serial_number='85430353531351B09121')
12
Eric
"""
Written on a Windows 10 Computer, Python 2.7.9 Version.

This program automatically detects and lists ports.  If no ports are found, it simply shells out.  In the printout below "list(serial.tools.list_ports.comports())" finds two ports and the program lists them out - a listout shown below:

     COM5 - USB-SERIAL CH340 (COM5)
     Found Arduino Uno on COM5
     COM4 - Microsoft USB GPS Port (COM4)

As each port is found, "CH340," (the name of the Adruino Uno) is searched for in the listed port with the "while int1 < 9:" loop.  The first "If" statement looks for "CH340" and when found the integer value "int1" will be the same as the com port #. With a concatination,  the operation "str1 = "COM" + str2" gives the com port name of the Adruino, eg. "COM5."  The next "IF" statement looks for both "CH340" AND str1, ("COM5") in the above case.  The statement "Found Arduino Uno on COM5" prints out, and "str1" is used in setting up the com port:

ser = serial.Serial(str1, 9600, timeout=10)

This program goes on to open the com port and prints data from the Adruino.

The modules "serial, sys, time, serial.tools.list_ports" must all be imported.

Written by Joseph F. Mack 01/29/2016.  "A BIG Thank you" to all the individuals whose programs I "borrowed" from that are available in the many forums for Python and PYGame users!
"""

import serial
import sys
import time
import serial.tools.list_ports

serPort = ""
int1 = 0
str1 = ""
str2 = ""

# Find Live Ports
ports = list(serial.tools.list_ports.comports())
for p in ports:
   print p # This causes each port's information to be printed out.
           # To search this p data, use p[1].

   while int1 < 9:   # Loop checks "COM0" to "COM8" for Adruino Port Info. 

      if "CH340" in p[1]:  # Looks for "CH340" in P[1].
            str2 = str(int1) # Converts an Integer to a String, allowing:
            str1 = "COM" + str2 # add the strings together.

      if "CH340" in p[1] and str1 in p[1]: # Looks for "CH340" and "COM#"
         print "Found Arduino Uno on " + str1
         int1 = 9 # Causes loop to end.

      if int1 == 8:
         print "UNO not found!"
         sys.exit() # Terminates Script.

      int1 = int1 + 1

time.sleep(5)  # Gives user 5 seconds to view Port information -- can be   changed/removed.

# Set Port
ser = serial.Serial(str1, 9600, timeout=10) # Put in your speed and timeout value.

# This begins the opening and printout of data from the Adruino.

ser.close()  # In case the port is already open this closes it.
ser.open()   # Reopen the port.

ser.flushInput()
ser.flushOutput()

int1 = 0
str1 = ""
str2 = ""

while int1==0:

   if "\n" not in str1:        # concatinates string on one line till a line feed "\n"
      str2 = ser.readline()    # is found, then prints the line.
      str1 += str2
   print(str1)
   str1=""
   time.sleep(.1)

print 'serial closed'
ser.close()
0
Joseph F. Mack

Versuchen Sie diesen Code (nur für Windows-Benutzer. MAC-Benutzer können die Idee von diesem Konzept zurückziehen)

import serial
import time
list=['COM1','COM2','COM3','COM4','COM5','COM6','COM7','COM8','COM9','COM10','COM11','COM12','COM13','COM14','COM15','COM16','COM17','COM18',]



COM1='COM1'
COM2='COM2'
COM3='COM3'
COM4='COM4'
COM5='COM5'
COM6='COM6'
COM7='COM7'
COM8='COM8'
COM9='COM9'
COM10='COM10'
COM11='COM11'
COM12='COM12'
COM13='COM13'
COM14='COM14'
COM15='COM15'
COM16='COM16'
COM17='COM17'
COM18='COM18'
COM19='COM19'
time.sleep(1)
ser = serial.Serial()

ser.baudrate = 9600

i=1

while True:
    time.sleep(.2)
    print(i)
    ser.port = list[i]
    try:

        ser.open()
        if ser.isOpen()==True:
            print('connected')
            #print('arduino is on COMPORT'.join(i))
            break
        break

    except:
        print('waiting')
        i=i+1
        if i==18:
            print('Kindly remove usb cable and try again')
            break


print('here we go')
while True:
    print(ser.readline())
0
Pardeep Singh